ASVAB Math Knowledge Practice Test 444475

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3a - 5a = 2a - x + 6 for a in terms of x.

1\(\frac{5}{6}\)x + \(\frac{1}{6}\)
-3\(\frac{1}{3}\)x - 1
-\(\frac{4}{7}\)x + \(\frac{4}{7}\)
-\(\frac{4}{5}\)x - 1\(\frac{1}{5}\)