ASVAB Math Knowledge Practice Test 445049 Results

Your Results Global Average
Questions 5 5
Correct 0 2.86
Score 0% 57%

Review

1

If a = c = 8, b = d = 9, and the blue angle = 69°, what is the area of this parallelogram?

65% Answer Correctly
72
10
32
48

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 8 x 9
a = 72


2

Solve for z:
4z - 1 = \( \frac{z}{8} \)

46% Answer Correctly
-10\(\frac{1}{8}\)
-\(\frac{7}{11}\)
\(\frac{8}{9}\)
\(\frac{8}{31}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

4z - 1 = \( \frac{z}{8} \)
8 x (4z - 1) = z
(8 x 4z) + (8 x -1) = z
32z - 8 = z
32z - 8 - z = 0
32z - z = 8
31z = 8
z = \( \frac{8}{31} \)
z = \(\frac{8}{31}\)


3

This diagram represents two parallel lines with a transversal. If w° = 32, what is the value of y°?

72% Answer Correctly
148
40
32
17

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with w° = 32, the value of y° is 148.


4

The dimensions of this cylinder are height (h) = 1 and radius (r) = 8. What is the surface area?

48% Answer Correctly
90π
36π
144π
192π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 1)
sa = 2π(64) + 2π(8)
sa = (2 x 64)π + (2 x 8)π
sa = 128π + 16π
sa = 144π


5

Solve for c:
c - 8 > -6 - 9c

54% Answer Correctly
c > -\(\frac{1}{6}\)
c > \(\frac{1}{5}\)
c > 1\(\frac{2}{5}\)
c > -1\(\frac{1}{2}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

c - 8 > -6 - 9c
c > -6 - 9c + 8
c + 9c > -6 + 8
10c > 2
c > \( \frac{2}{10} \)
c > \(\frac{1}{5}\)