ASVAB Math Knowledge Practice Test 445265

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9a + 7a = -3a - 4z - 8 for a in terms of z.

1\(\frac{5}{6}\)z + 1\(\frac{1}{3}\)
\(\frac{1}{2}\)z - 2\(\frac{1}{2}\)
-\(\frac{6}{7}\)z + \(\frac{9}{14}\)
3z + 1