ASVAB Math Knowledge Practice Test 446223 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

Simplify (6a)(4ab) + (3a2)(5b).

65% Answer Correctly
80ab2
9ab2
39a2b
9a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(4ab) + (3a2)(5b)
(6 x 4)(a x a x b) + (3 x 5)(a2 x b)
(24)(a1+1 x b) + (15)(a2b)
24a2b + 15a2b
39a2b


2

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

division

exponents

pairs

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


3

If side a = 2, side b = 3, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{128} \)
\( \sqrt{50} \)
\( \sqrt{13} \)
\( \sqrt{5} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 32
c2 = 4 + 9
c2 = 13
c = \( \sqrt{13} \)


4

On this circle, line segment CD is the:

46% Answer Correctly

diameter

circumference

chord

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for y:
-2y - 5 < \( \frac{y}{-1} \)

44% Answer Correctly
y < -\(\frac{16}{19}\)
y < -5
y < -\(\frac{3}{5}\)
y < \(\frac{4}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-2y - 5 < \( \frac{y}{-1} \)
-1 x (-2y - 5) < y
(-1 x -2y) + (-1 x -5) < y
2y + 5 < y
2y + 5 - y < 0
2y - y < -5
y < -5
y < \( \frac{-5}{1} \)
y < -5