| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
Simplify (6a)(4ab) + (3a2)(5b).
| 80ab2 | |
| 9ab2 | |
| 39a2b | |
| 9a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(4ab) + (3a2)(5b)
(6 x 4)(a x a x b) + (3 x 5)(a2 x b)
(24)(a1+1 x b) + (15)(a2b)
24a2b + 15a2b
39a2b
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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exponents |
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pairs |
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addition |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
If side a = 2, side b = 3, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{128} \) | |
| \( \sqrt{50} \) | |
| \( \sqrt{13} \) | |
| \( \sqrt{5} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 22 + 32
c2 = 4 + 9
c2 = 13
c = \( \sqrt{13} \)
On this circle, line segment CD is the:
diameter |
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circumference |
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chord |
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radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve for y:
-2y - 5 < \( \frac{y}{-1} \)
| y < -\(\frac{16}{19}\) | |
| y < -5 | |
| y < -\(\frac{3}{5}\) | |
| y < \(\frac{4}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-2y - 5 < \( \frac{y}{-1} \)
-1 x (-2y - 5) < y
(-1 x -2y) + (-1 x -5) < y
2y + 5 < y
2y + 5 - y < 0
2y - y < -5
y < -5
y < \( \frac{-5}{1} \)
y < -5