| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
If the base of this triangle is 8 and the height is 7, what is the area?
| 28 | |
| 67\(\frac{1}{2}\) | |
| 70 | |
| 82\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 8 x 7 = \( \frac{56}{2} \) = 28
If a = 9, b = 5, c = 3, and d = 9, what is the perimeter of this quadrilateral?
| 24 | |
| 26 | |
| 17 | |
| 16 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 9 + 5 + 3 + 9
p = 26
The dimensions of this trapezoid are a = 5, b = 7, c = 7, d = 9, and h = 4. What is the area?
| 24 | |
| 32 | |
| 16\(\frac{1}{2}\) | |
| 26 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(7 + 9)(4)
a = ½(16)(4)
a = ½(64) = \( \frac{64}{2} \)
a = 32
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
|
c2 + a2 |
|
c2 - a2 |
|
c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Factor y2 - 11y + 18
| (y + 9)(y - 2) | |
| (y + 9)(y + 2) | |
| (y - 9)(y - 2) | |
| (y - 9)(y + 2) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 18 as well and sum (Inside, Outside) to equal -11. For this problem, those two numbers are -9 and -2. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 11y + 18
y2 + (-9 - 2)y + (-9 x -2)
(y - 9)(y - 2)