ASVAB Math Knowledge Practice Test 447238

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2b + 4b = -2b + 9z + 9 for b in terms of z.

\(\frac{1}{7}\)z + \(\frac{5}{7}\)
1\(\frac{1}{4}\)z + 2\(\frac{1}{4}\)
17z + 8
-3\(\frac{2}{3}\)z + 2\(\frac{1}{3}\)