ASVAB Math Knowledge Practice Test 44750 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

83% Answer Correctly

First

Last

Inside

Odd


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


2

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
9\( \sqrt{2} \)
5\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


3

If side x = 5cm, side y = 15cm, and side z = 7cm what is the perimeter of this triangle?

84% Answer Correctly
35cm
27cm
22cm
28cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 5cm + 15cm + 7cm = 27cm


4

If angle a = 31° and angle b = 66° what is the length of angle c?

70% Answer Correctly
114°
79°
104°
83°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 31° - 66° = 83°


5

Solve 9c - 8c = c - y - 9 for c in terms of y.

34% Answer Correctly
-\(\frac{2}{3}\)y + \(\frac{5}{12}\)
-3\(\frac{1}{2}\)y - 2
2\(\frac{1}{3}\)y + 2
\(\frac{7}{8}\)y - 1\(\frac{1}{8}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

9c - 8y = c - y - 9
9c = c - y - 9 + 8y
9c - c = -y - 9 + 8y
8c = 7y - 9
c = \( \frac{7y - 9}{8} \)
c = \( \frac{7y}{8} \) + \( \frac{-9}{8} \)
c = \(\frac{7}{8}\)y - 1\(\frac{1}{8}\)