When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2a + 8a = 2a + 2z + 1 for a in terms of z.
| 1\(\frac{2}{5}\)z - 1\(\frac{1}{5}\) | |
| 5z - 3\(\frac{1}{2}\) | |
| 1\(\frac{1}{2}\)z - \(\frac{1}{4}\) | |
| z + 1\(\frac{1}{6}\) |