When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 4c = 5c - x + 2 for c in terms of x.
| \(\frac{1}{3}\)x - 1 | |
| -5x - 4 | |
| \(\frac{1}{2}\)x - \(\frac{1}{5}\) | |
| \(\frac{2}{9}\)x - \(\frac{1}{3}\) |