When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 6c = -3c + 6z - 8 for c in terms of z.
| 1\(\frac{5}{6}\)z - \(\frac{1}{2}\) | |
| -\(\frac{7}{10}\)z - \(\frac{1}{2}\) | |
| -\(\frac{9}{11}\)z + \(\frac{1}{11}\) | |
| z + 1\(\frac{3}{5}\) |