ASVAB Math Knowledge Practice Test 448533

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4b - 4b = 2b + 5z - 4 for b in terms of z.

-3z - 5
z - \(\frac{3}{5}\)
4\(\frac{1}{2}\)z - 2
1\(\frac{1}{2}\)z - 2