| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
vertical, supplementary |
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acute, obtuse |
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supplementary, vertical |
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obtuse, acute |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
On this circle, a line segment connecting point A to point D is called:
chord |
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circumference |
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radius |
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diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
A right angle measures:
45° |
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360° |
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180° |
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90° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
What is 4a - 5a?
| 20a | |
| -1a | |
| 20a2 | |
| -a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a - 5a = -1a
Solve for a:
a2 - 5a + 29 = 5a + 5
| 8 or -2 | |
| 6 or -4 | |
| -6 or -7 | |
| 4 or 6 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
a2 - 5a + 29 = 5a + 5
a2 - 5a + 29 - 5 = 5a
a2 - 5a - 5a + 24 = 0
a2 - 10a + 24 = 0
Next, factor the quadratic equation:
a2 - 10a + 24 = 0
(a - 4)(a - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (a - 4) or (a - 6) must equal zero:
If (a - 4) = 0, a must equal 4
If (a - 6) = 0, a must equal 6
So the solution is that a = 4 or 6