ASVAB Math Knowledge Practice Test 450393

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 10b + 3b = 9b + 6z - 2 for b in terms of z.

-5\(\frac{1}{2}\)z + \(\frac{1}{2}\)
3z - 2
\(\frac{2}{3}\)z + \(\frac{1}{3}\)
-3z - 2