When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + 2c = -c + 3z + 6 for c in terms of z.
| 1\(\frac{4}{9}\)z - \(\frac{5}{9}\) | |
| 1\(\frac{1}{5}\)z + \(\frac{3}{5}\) | |
| \(\frac{1}{2}\)z + 3 | |
| -\(\frac{5}{12}\)z + \(\frac{7}{12}\) |