ASVAB Math Knowledge Practice Test 45332 Results

Your Results Global Average
Questions 5 5
Correct 0 2.56
Score 0% 51%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

2(π r2) + 2π rh

4π r2

π r2h2

π r2h


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

diameter

circumference

chord

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c2 + a2

c - a

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


4

Solve -7a + a = 2a - 6z + 2 for a in terms of z.

34% Answer Correctly
2z + 2\(\frac{1}{2}\)
-\(\frac{1}{3}\)z - 2\(\frac{2}{3}\)
\(\frac{7}{9}\)z - \(\frac{2}{9}\)
z + 2\(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-7a + z = 2a - 6z + 2
-7a = 2a - 6z + 2 - z
-7a - 2a = -6z + 2 - z
-9a = -7z + 2
a = \( \frac{-7z + 2}{-9} \)
a = \( \frac{-7z}{-9} \) + \( \frac{2}{-9} \)
a = \(\frac{7}{9}\)z - \(\frac{2}{9}\)


5

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

normalizing

squaring

deconstructing

factoring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.