| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.69 |
| Score | 0% | 54% |
The dimensions of this trapezoid are a = 5, b = 2, c = 8, d = 5, and h = 4. What is the area?
| 14 | |
| 32 | |
| 22 | |
| 24 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(2 + 5)(4)
a = ½(7)(4)
a = ½(28) = \( \frac{28}{2} \)
a = 14
Which of the following expressions contains exactly two terms?
binomial |
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quadratic |
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polynomial |
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monomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Which of the following statements about parallel lines with a transversal is not correct?
all acute angles equal each other |
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same-side interior angles are complementary and equal each other |
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all of the angles formed by a transversal are called interior angles |
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angles in the same position on different parallel lines are called corresponding angles |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
A(n) __________ is to a parallelogram as a square is to a rectangle.
rhombus |
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triangle |
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trapezoid |
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quadrilateral |
A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.
Solve for b:
-6b + 9 > \( \frac{b}{2} \)
| b > 2\(\frac{1}{10}\) | |
| b > 1\(\frac{5}{13}\) | |
| b > -\(\frac{16}{47}\) | |
| b > -1\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-6b + 9 > \( \frac{b}{2} \)
2 x (-6b + 9) > b
(2 x -6b) + (2 x 9) > b
-12b + 18 > b
-12b + 18 - b > 0
-12b - b > -18
-13b > -18
b > \( \frac{-18}{-13} \)
b > 1\(\frac{5}{13}\)