ASVAB Math Knowledge Practice Test 453612

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b - 4b = b - z - 7 for b in terms of z.

-1\(\frac{1}{2}\)z + 3\(\frac{1}{2}\)
-\(\frac{2}{7}\)z - \(\frac{3}{7}\)
1\(\frac{1}{5}\)z - 1\(\frac{3}{5}\)
-z - 2