When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 8c = c + 2z - 4 for c in terms of z.
| -1\(\frac{1}{9}\)z + 1 | |
| -2z - 1\(\frac{1}{3}\) | |
| \(\frac{13}{14}\)z - \(\frac{4}{7}\) | |
| \(\frac{1}{14}\)z - \(\frac{1}{14}\) |