ASVAB Math Knowledge Practice Test 455512

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c - 5c = -2c + 6y + 7 for c in terms of y.

17y - 1
-1\(\frac{2}{3}\)y - 2\(\frac{1}{3}\)
2\(\frac{3}{4}\)y + 1\(\frac{3}{4}\)
\(\frac{1}{3}\)y - 1\(\frac{1}{3}\)