When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 5c = -6c + 3y + 4 for c in terms of y.
| \(\frac{2}{13}\)y - \(\frac{5}{13}\) | |
| -\(\frac{1}{6}\)y + \(\frac{1}{3}\) | |
| -\(\frac{1}{2}\)y + \(\frac{7}{10}\) | |
| 3\(\frac{1}{2}\)y - 4\(\frac{1}{2}\) |