ASVAB Math Knowledge Practice Test 458773

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a - 2a = 5a + 4y + 2 for a in terms of y.

6y + 2
3\(\frac{1}{4}\)y - 2
-5y + 2\(\frac{2}{3}\)
-\(\frac{2}{3}\)y + \(\frac{1}{6}\)