When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c - 7c = -3c + 6z + 3 for c in terms of z.
| \(\frac{1}{3}\)z - \(\frac{3}{4}\) | |
| -4\(\frac{1}{3}\)z - 1 | |
| -\(\frac{3}{5}\)z + 1\(\frac{1}{5}\) | |
| 2z + \(\frac{1}{5}\) |