| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.83 |
| Score | 0% | 57% |
Factor y2 + y - 6
| (y - 2)(y + 3) | |
| (y - 2)(y - 3) | |
| (y + 2)(y + 3) | |
| (y + 2)(y - 3) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -6 as well and sum (Inside, Outside) to equal 1. For this problem, those two numbers are -2 and 3. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + y - 6
y2 + (-2 + 3)y + (-2 x 3)
(y - 2)(y + 3)
If b = 4 and y = 2, what is the value of -5b(b - y)?
| 20 | |
| 24 | |
| -40 | |
| 612 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-5b(b - y)
-5(4)(4 - 2)
-5(4)(2)
(-20)(2)
-40
Solve for b:
6b - 1 = -9 + 9b
| -2\(\frac{1}{4}\) | |
| 5 | |
| 2\(\frac{2}{3}\) | |
| -1\(\frac{3}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
6b - 1 = -9 + 9b
6b = -9 + 9b + 1
6b - 9b = -9 + 1
-3b = -8
b = \( \frac{-8}{-3} \)
b = 2\(\frac{2}{3}\)
The dimensions of this cylinder are height (h) = 1 and radius (r) = 5. What is the surface area?
| 36π | |
| 60π | |
| 64π | |
| 192π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 1)
sa = 2π(25) + 2π(5)
sa = (2 x 25)π + (2 x 5)π
sa = 50π + 10π
sa = 60π
The dimensions of this cube are height (h) = 9, length (l) = 4, and width (w) = 2. What is the surface area?
| 52 | |
| 190 | |
| 124 | |
| 76 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 2) + (2 x 2 x 9) + (2 x 4 x 9)
sa = (16) + (36) + (72)
sa = 124