| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
What is the area of a circle with a radius of 3?
| 64π | |
| 9π | |
| 4π | |
| 49π |
The formula for area is πr2:
a = πr2
a = π(32)
a = 9π
If the base of this triangle is 9 and the height is 6, what is the area?
| 65 | |
| 72 | |
| 27 | |
| 45 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 6 = \( \frac{54}{2} \) = 27
What is 7a3 - 7a3?
| 0a3 | |
| 0 | |
| 6 | |
| 49a3 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a3 - 7a3 = 0a3
Solve for y:
y - 3 = \( \frac{y}{-4} \)
| \(\frac{3}{17}\) | |
| 2\(\frac{2}{5}\) | |
| -1\(\frac{3}{7}\) | |
| \(\frac{3}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
y - 3 = \( \frac{y}{-4} \)
-4 x (y - 3) = y
(-4 x y) + (-4 x -3) = y
-4y + 12 = y
-4y + 12 - y = 0
-4y - y = -12
-5y = -12
y = \( \frac{-12}{-5} \)
y = 2\(\frac{2}{5}\)
This diagram represents two parallel lines with a transversal. If y° = 148, what is the value of d°?
| 39 | |
| 148 | |
| 169 | |
| 19 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with y° = 148, the value of d° is 148.