ASVAB Math Knowledge Practice Test 461465

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c + 4c = 5c - 5x + 2 for c in terms of x.

-9x + 2
-2\(\frac{1}{4}\)x - \(\frac{1}{4}\)
\(\frac{1}{2}\)x - 1\(\frac{1}{2}\)
x - 1