| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.58 |
| Score | 0% | 52% |
The formula for the area of a circle is which of the following?
c = π d2 |
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c = π r2 |
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c = π r |
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c = π d |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
On this circle, a line segment connecting point A to point D is called:
diameter |
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chord |
|
circumference |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The dimensions of this trapezoid are a = 4, b = 6, c = 5, d = 2, and h = 3. What is the area?
| 15 | |
| 28 | |
| 20 | |
| 12 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(6 + 2)(3)
a = ½(8)(3)
a = ½(24) = \( \frac{24}{2} \)
a = 12
If the area of this square is 81, what is the length of one of the diagonals?
| 6\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)
What is the area of a circle with a radius of 2?
| 5π | |
| 64π | |
| 25π | |
| 4π |
The formula for area is πr2:
a = πr2
a = π(22)
a = 4π