| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.23 |
| Score | 0% | 65% |
What is 4a - 8a?
| -4a2 | |
| 32a2 | |
| -4a | |
| a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
4a - 8a = -4a
Simplify (5a)(9ab) + (9a2)(8b).
| 238ab2 | |
| 117a2b | |
| -27ab2 | |
| 27a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(9ab) + (9a2)(8b)
(5 x 9)(a x a x b) + (9 x 8)(a2 x b)
(45)(a1+1 x b) + (72)(a2b)
45a2b + 72a2b
117a2b
Solve for x:
x2 + 7x + 23 = -4x + 5
| 6 or 5 | |
| 8 or 1 | |
| 8 or -1 | |
| -2 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
x2 + 7x + 23 = -4x + 5
x2 + 7x + 23 - 5 = -4x
x2 + 7x + 4x + 18 = 0
x2 + 11x + 18 = 0
Next, factor the quadratic equation:
x2 + 11x + 18 = 0
(x + 2)(x + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 2) or (x + 9) must equal zero:
If (x + 2) = 0, x must equal -2
If (x + 9) = 0, x must equal -9
So the solution is that x = -2 or -9
Which of the following is not true about both rectangles and squares?
the area is length x width |
|
the perimeter is the sum of the lengths of all four sides |
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the lengths of all sides are equal |
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all interior angles are right angles |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
If c = 5 and y = -8, what is the value of -7c(c - y)?
| 72 | |
| -455 | |
| -200 | |
| 588 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-7c(c - y)
-7(5)(5 + 8)
-7(5)(13)
(-35)(13)
-455