ASVAB Math Knowledge Practice Test 464495

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4b - 4b = 5b + 5z + 4 for b in terms of z.

\(\frac{1}{13}\)z - \(\frac{2}{13}\)
4z + 4\(\frac{1}{2}\)
-\(\frac{5}{8}\)z + \(\frac{1}{2}\)
-9z - 4