| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.52 |
| Score | 0% | 50% |
The dimensions of this cylinder are height (h) = 8 and radius (r) = 4. What is the surface area?
| 96π | |
| 198π | |
| 120π | |
| 60π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(42) + 2π(4 x 8)
sa = 2π(16) + 2π(32)
sa = (2 x 16)π + (2 x 32)π
sa = 32π + 64π
sa = 96π
The dimensions of this cube are height (h) = 1, length (l) = 6, and width (w) = 4. What is the surface area?
| 180 | |
| 126 | |
| 172 | |
| 68 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 6 x 4) + (2 x 4 x 1) + (2 x 6 x 1)
sa = (48) + (8) + (12)
sa = 68
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
|
c - a |
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c2 - a2 |
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c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Which of the following statements about math operations is incorrect?
you can multiply monomials that have different variables and different exponents |
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you can add monomials that have the same variable and the same exponent |
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you can subtract monomials that have the same variable and the same exponent |
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all of these statements are correct |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Solve -9b - 8b = -2b - 5x - 7 for b in terms of x.
| -\(\frac{3}{7}\)x + 1 | |
| x + 3\(\frac{1}{2}\) | |
| x - \(\frac{2}{3}\) | |
| \(\frac{1}{6}\)x - \(\frac{3}{4}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-9b - 8x = -2b - 5x - 7
-9b = -2b - 5x - 7 + 8x
-9b + 2b = -5x - 7 + 8x
-7b = 3x - 7
b = \( \frac{3x - 7}{-7} \)
b = \( \frac{3x}{-7} \) + \( \frac{-7}{-7} \)
b = -\(\frac{3}{7}\)x + 1