When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + c = 8c + x + 5 for c in terms of x.
| -\(\frac{2}{3}\)x + \(\frac{1}{2}\) | |
| x - 2\(\frac{1}{2}\) | |
| -\(\frac{5}{6}\)x + \(\frac{3}{4}\) | |
| 2\(\frac{1}{3}\)x - 1\(\frac{1}{6}\) |