| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
Solve for y:
y2 - 13y - 4 = -5y + 5
| 6 or -1 | |
| 5 or -6 | |
| 5 or -5 | |
| -1 or 9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 - 13y - 4 = -5y + 5
y2 - 13y - 4 - 5 = -5y
y2 - 13y + 5y - 9 = 0
y2 - 8y - 9 = 0
Next, factor the quadratic equation:
y2 - 8y - 9 = 0
(y + 1)(y - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 1) or (y - 9) must equal zero:
If (y + 1) = 0, y must equal -1
If (y - 9) = 0, y must equal 9
So the solution is that y = -1 or 9
What is 8a - 7a?
| 1a | |
| 56a | |
| 15a2 | |
| a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a - 7a = 1a
Simplify (y - 1)(y - 4)
| y2 + 5y + 4 | |
| y2 - 5y + 4 | |
| y2 + 3y - 4 | |
| y2 - 3y - 4 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y - 1)(y - 4)
(y x y) + (y x -4) + (-1 x y) + (-1 x -4)
y2 - 4y - y + 4
y2 - 5y + 4
If the base of this triangle is 6 and the height is 3, what is the area?
| 24\(\frac{1}{2}\) | |
| 9 | |
| 24 | |
| 84 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 6 x 3 = \( \frac{18}{2} \) = 9
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
|
obtuse, acute |
|
acute, obtuse |
|
vertical, supplementary |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).