When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8b + 3b = b - 4y + 1 for b in terms of y.
| 2\(\frac{1}{2}\)y - 1\(\frac{1}{2}\) | |
| -y + \(\frac{1}{7}\) | |
| 1\(\frac{2}{3}\)y + \(\frac{1}{2}\) | |
| \(\frac{1}{2}\)y - \(\frac{1}{2}\) |