When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 5c = 8c - 8z - 5 for c in terms of z.
| -\(\frac{3}{4}\)z + \(\frac{3}{8}\) | |
| \(\frac{5}{7}\)z + 1\(\frac{2}{7}\) | |
| 1\(\frac{1}{3}\)z + \(\frac{8}{9}\) | |
| 2\(\frac{1}{6}\)z + \(\frac{5}{6}\) |