When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 6c = 7c + x - 5 for c in terms of x.
| 3\(\frac{1}{3}\)x - 1 | |
| \(\frac{5}{12}\)x + \(\frac{5}{12}\) | |
| \(\frac{1}{2}\)x + \(\frac{3}{4}\) | |
| -2\(\frac{1}{2}\)x - 1 |