ASVAB Math Knowledge Practice Test 468489 Results

Your Results Global Average
Questions 5 5
Correct 0 2.33
Score 0% 47%

Review

1

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

\({\Delta y \over \Delta x}\)

x-intercept

y-intercept

slope


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


2

The dimensions of this cube are height (h) = 4, length (l) = 2, and width (w) = 5. What is the surface area?

51% Answer Correctly
138
76
118
198

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 2 x 5) + (2 x 5 x 4) + (2 x 2 x 4)
sa = (20) + (40) + (16)
sa = 76


3

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π d

c = π d2

c = π r

c = π r2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


4

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

π r2h

π r2h2

2(π r2) + 2π rh

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

If side a = 7, side b = 3, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{26} \)
\( \sqrt{113} \)
\( \sqrt{52} \)
\( \sqrt{58} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 72 + 32
c2 = 49 + 9
c2 = 58
c = \( \sqrt{58} \)