ASVAB Math Knowledge Practice Test 468806

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4b - 2b = 6b + 9z + 5 for b in terms of z.

\(\frac{5}{14}\)z + \(\frac{5}{14}\)
-5\(\frac{1}{2}\)z - 2\(\frac{1}{2}\)
5z - 2\(\frac{2}{3}\)
-\(\frac{1}{5}\)z + 1\(\frac{2}{5}\)