ASVAB Math Knowledge Practice Test 469155 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

Solve for b:
9b - 3 = 3 + b

60% Answer Correctly
\(\frac{3}{4}\)
-\(\frac{5}{8}\)
-\(\frac{8}{9}\)
-\(\frac{4}{9}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

9b - 3 = 3 + b
9b = 3 + b + 3
9b - b = 3 + 3
8b = 6
b = \( \frac{6}{8} \)
b = \(\frac{3}{4}\)


2

The dimensions of this cylinder are height (h) = 4 and radius (r) = 1. What is the surface area?

48% Answer Correctly
198π
10π
12π
64π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 4)
sa = 2π(1) + 2π(4)
sa = (2 x 1)π + (2 x 4)π
sa = 2π + 8π
sa = 10π


3

Simplify (y - 6)(y - 1)

64% Answer Correctly
y2 + 5y - 6
y2 + 7y + 6
y2 - 7y + 6
y2 - 5y - 6

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y - 6)(y - 1)
(y x y) + (y x -1) + (-6 x y) + (-6 x -1)
y2 - y - 6y + 6
y2 - 7y + 6


4

A trapezoid is a quadrilateral with one set of __________ sides.

71% Answer Correctly

equal angle

equal length

right angle

parallel


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


5

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

4π r2

π r2h

π r2h2

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.