ASVAB Math Knowledge Practice Test 470545 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

If a = c = 9, b = d = 3, what is the area of this rectangle?

80% Answer Correctly
27
16
8
6

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 9 x 3
a = 27


2

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

92% Answer Correctly

division

addition

pairs

exponents


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


3

Solve for c:
-8c + 9 = \( \frac{c}{3} \)

46% Answer Correctly
-2\(\frac{10}{13}\)
-1\(\frac{6}{29}\)
1\(\frac{2}{25}\)
-1\(\frac{1}{44}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-8c + 9 = \( \frac{c}{3} \)
3 x (-8c + 9) = c
(3 x -8c) + (3 x 9) = c
-24c + 27 = c
-24c + 27 - c = 0
-24c - c = -27
-25c = -27
c = \( \frac{-27}{-25} \)
c = 1\(\frac{2}{25}\)


4

A(n) __________ is two expressions separated by an equal sign.

77% Answer Correctly

equation

expression

formula

problem


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


5

Solve 2b + 9b = -9b - 2z + 3 for b in terms of z.

35% Answer Correctly
-\(\frac{1}{11}\)z + \(\frac{2}{11}\)
-z + \(\frac{3}{11}\)
7z + 2
\(\frac{2}{5}\)z + 1\(\frac{1}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

2b + 9z = -9b - 2z + 3
2b = -9b - 2z + 3 - 9z
2b + 9b = -2z + 3 - 9z
11b = -11z + 3
b = \( \frac{-11z + 3}{11} \)
b = \( \frac{-11z}{11} \) + \( \frac{3}{11} \)
b = -z + \(\frac{3}{11}\)