| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
Factor y2 + y - 2
| (y + 1)(y - 2) | |
| (y - 1)(y + 2) | |
| (y + 1)(y + 2) | |
| (y - 1)(y - 2) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -2 as well and sum (Inside, Outside) to equal 1. For this problem, those two numbers are -1 and 2. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + y - 2
y2 + (-1 + 2)y + (-1 x 2)
(y - 1)(y + 2)
Simplify (8a)(5ab) + (4a2)(7b).
| -12ab2 | |
| 143a2b | |
| 68a2b | |
| 143ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(5ab) + (4a2)(7b)
(8 x 5)(a x a x b) + (4 x 7)(a2 x b)
(40)(a1+1 x b) + (28)(a2b)
40a2b + 28a2b
68a2b
For this diagram, the Pythagorean theorem states that b2 = ?
c - a |
|
c2 + a2 |
|
a2 - c2 |
|
c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
What is 5a + 2a?
| 7 | |
| 3a2 | |
| 3 | |
| 7a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a + 2a = 7a
If side x = 11cm, side y = 9cm, and side z = 15cm what is the perimeter of this triangle?
| 33cm | |
| 37cm | |
| 42cm | |
| 35cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 11cm + 9cm + 15cm = 35cm