When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 8c = 2c - x - 4 for c in terms of x.
| -2\(\frac{1}{4}\)x - 1 | |
| \(\frac{11}{13}\)x - \(\frac{5}{13}\) | |
| \(\frac{1}{4}\)x - 1\(\frac{3}{4}\) | |
| \(\frac{1}{5}\)x - \(\frac{7}{15}\) |