| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.80 |
| Score | 0% | 56% |
Simplify (4a)(6ab) - (4a2)(6b).
| 48a2b | |
| 0a2b | |
| 2b | |
| b2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(6ab) - (4a2)(6b)
(4 x 6)(a x a x b) - (4 x 6)(a2 x b)
(24)(a1+1 x b) - (24)(a2b)
24a2b - 24a2b
0a2b
Simplify (5a)(5ab) + (6a2)(5b).
| 55a2b | |
| 5a2b | |
| 110a2b | |
| -5a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(5ab) + (6a2)(5b)
(5 x 5)(a x a x b) + (6 x 5)(a2 x b)
(25)(a1+1 x b) + (30)(a2b)
25a2b + 30a2b
55a2b
Find the value of c:
-4c + x = 6
7c - 5x = -8
| -2\(\frac{5}{34}\) | |
| -1\(\frac{1}{8}\) | |
| -1\(\frac{9}{13}\) | |
| -\(\frac{5}{6}\) |
You need to find the value of c so solve the first equation in terms of x:
-4c + x = 6
x = 6 + 4c
then substitute the result (6 - -4c) into the second equation:
7c - 5(6 + 4c) = -8
7c + (-5 x 6) + (-5 x 4c) = -8
7c - 30 - 20c = -8
7c - 20c = -8 + 30
-13c = 22
c = \( \frac{22}{-13} \)
c = -1\(\frac{9}{13}\)
Which of the following is not true about both rectangles and squares?
the area is length x width |
|
the perimeter is the sum of the lengths of all four sides |
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the lengths of all sides are equal |
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all interior angles are right angles |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
The endpoints of this line segment are at (-2, 8) and (2, -4). What is the slope of this line?
| -1 | |
| \(\frac{1}{2}\) | |
| -1\(\frac{1}{2}\) | |
| -3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 8) and (2, -4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (8.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)