When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6a + a = -a - 4z - 3 for a in terms of z.
| -\(\frac{1}{2}\)z + 1\(\frac{1}{8}\) | |
| -\(\frac{5}{7}\)z - \(\frac{3}{7}\) | |
| 4z - 8 | |
| -4\(\frac{3}{4}\)z + \(\frac{1}{4}\) |