When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + 5c = -6c - 4z + 9 for c in terms of z.
| -1\(\frac{4}{5}\)z - 1\(\frac{1}{5}\) | |
| -1\(\frac{5}{6}\)z + \(\frac{1}{2}\) | |
| \(\frac{1}{7}\)z + \(\frac{3}{14}\) | |
| -1\(\frac{2}{7}\)z + 1\(\frac{2}{7}\) |