When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 8c = -8c - 6y + 4 for c in terms of y.
| -1\(\frac{3}{11}\)y + \(\frac{4}{11}\) | |
| -2y - \(\frac{2}{3}\) | |
| -y - \(\frac{4}{9}\) | |
| -\(\frac{3}{14}\)y - \(\frac{1}{7}\) |