| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
Solve for y:
4y - 5 = 7 - y
| 1\(\frac{1}{8}\) | |
| 2\(\frac{2}{5}\) | |
| 3 | |
| \(\frac{1}{6}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
4y - 5 = 7 - y
4y = 7 - y + 5
4y + y = 7 + 5
5y = 12
y = \( \frac{12}{5} \)
y = 2\(\frac{2}{5}\)
On this circle, line segment CD is the:
chord |
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circumference |
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diameter |
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radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
pairs |
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division |
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addition |
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exponents |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Which types of triangles will always have at least two sides of equal length?
equilateral, isosceles and right |
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isosceles and right |
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equilateral and isosceles |
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equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Solve for b:
5b + 5 < \( \frac{b}{-7} \)
| b < 2\(\frac{10}{13}\) | |
| b < -\(\frac{3}{7}\) | |
| b < -\(\frac{35}{36}\) | |
| b < \(\frac{7}{25}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
5b + 5 < \( \frac{b}{-7} \)
-7 x (5b + 5) < b
(-7 x 5b) + (-7 x 5) < b
-35b - 35 < b
-35b - 35 - b < 0
-35b - b < 35
-36b < 35
b < \( \frac{35}{-36} \)
b < -\(\frac{35}{36}\)