| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
What is 9a + 2a?
| 11 | |
| 11a | |
| 7a2 | |
| 7 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
9a + 2a = 11a
Factor y2 - 4y - 5
| (y - 5)(y - 1) | |
| (y - 5)(y + 1) | |
| (y + 5)(y - 1) | |
| (y + 5)(y + 1) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -5 as well and sum (Inside, Outside) to equal -4. For this problem, those two numbers are -5 and 1. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 4y - 5
y2 + (-5 + 1)y + (-5 x 1)
(y - 5)(y + 1)
If side a = 1, side b = 5, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{8} \) | |
| \( \sqrt{85} \) | |
| \( \sqrt{65} \) | |
| \( \sqrt{26} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 12 + 52
c2 = 1 + 25
c2 = 26
c = \( \sqrt{26} \)
If angle a = 24° and angle b = 30° what is the length of angle d?
| 112° | |
| 111° | |
| 156° | |
| 155° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 24° - 30° = 126°
So, d° = 30° + 126° = 156°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 24° = 156°
Simplify (7a)(5ab) + (4a2)(2b).
| -27a2b | |
| 72ab2 | |
| 43a2b | |
| 27a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(5ab) + (4a2)(2b)
(7 x 5)(a x a x b) + (4 x 2)(a2 x b)
(35)(a1+1 x b) + (8)(a2b)
35a2b + 8a2b
43a2b