ASVAB Math Knowledge Practice Test 478423

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a + 5a = 7a - z - 4 for a in terms of z.

2z + 1\(\frac{1}{3}\)
4\(\frac{1}{4}\)z + 2\(\frac{1}{4}\)
-\(\frac{1}{3}\)z + 1\(\frac{1}{6}\)
-1\(\frac{5}{6}\)z + 1