ASVAB Math Knowledge Practice Test 47914

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2b + 4b = b + 3z - 4 for b in terms of z.

-z - 4
-2\(\frac{1}{2}\)z - 4\(\frac{1}{2}\)
\(\frac{1}{8}\)z + \(\frac{1}{4}\)
-\(\frac{3}{5}\)z + \(\frac{1}{5}\)