ASVAB Math Knowledge Practice Test 479894

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -5c - 4c = 7c + 5x - 2 for c in terms of x.

\(\frac{1}{3}\)x - \(\frac{1}{3}\)
5\(\frac{1}{2}\)x + \(\frac{1}{2}\)
\(\frac{15}{16}\)x - \(\frac{1}{2}\)
-\(\frac{3}{4}\)x + \(\frac{1}{6}\)