ASVAB Math Knowledge Practice Test 480912

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4a - 6a = 5a + 3z + 2 for a in terms of z.

-\(\frac{1}{3}\)z - 2
-z - \(\frac{2}{9}\)
-\(\frac{1}{3}\)z - 3
13z + 2